Question

when a mass of 1 kg is suspended from a vertical spring, it's length increases by 0.98m.if this mass
pulled downwards and then released, what will be periodic time of vibration of spring ?g=9.8m/s^2​

Answer 1

Dear Student,

◆ Answer -

T = 1.987 s

● Explaination -

# Given -

m = 1 kg

l = 0.98 m

g = 9.8 m/s²

# Solution -

Periodic time of vibration of spring is -

T = 2π √(l/g)

T = 2 × 3.142 × √(0.98/9.8)

T = 6.284 × 1/√10

T = 6.284 / √10

T = 1.987 s

Therefore, periodic time of vibration of spring is 1.987 s.

Thanks dear. Hope this helps you....