Question

When a mass of 1000 g moves with an acceleration of 1 m/s^2, the force acting is​

Answer 1

Answer:-

$\red{\bigstar}$ Force acting $\large\leadsto\boxed{\bf\pink{1 \: N}}$

• Given:-

• Mass of a body = 1000g = 1kg

• Acceleration = 1 m/s²

• To Find:-

• Force acting on the body.

• Solution:-

We know,

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\purple{F = ma}}}$

where,

• F = Force acting on the body

• m = mass of the body

• a = acceleration

• Substituting in the values:-

➪ $\sf F = 1 kg \times 1 \: m/s^2$

➪ $\sf F = 1 kg.m.s^{-2}$

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{1 \: kg.m.s^{-2} = 1 \: N}}}$

Hence,

➪ $\large{\bf\red{F = 1 \: N}}$

Therefore, the fore acting on the body is of 1 N.

Answer 2

Answer:

The mass of the lift is 1000kg, the acceleration is 1m/s

2

and the acceleration due to gravity is 9.8m/s

2

.

The tension developed in string is given as,

T=mg+ma

=1000×9.8+1000×1

=10800N

Thus, the tension developed in the string is 10800N...