When a metal is burned its weight is increased by 24 the equivalent weight of the metal will be?
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"Equivalent weight of O^2-(oxide) ion is : Molar mass of oxygen/ charge of oxygen
= 16 g mol^-1 /2 mol eq^-1
= 8 g eq^-1
Let us consider M to be the equivalent weight of the metal.
Therefore when M grams of the metal will react with 8g of oxygen the corresponding metal oxide formed will be 8gm more in Mass. This 8 gram is 24% of M.
Or we can say that M x 24/100 = 8 gram
So, M = 100 x 8/24 = 33.33 g
"
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