When a metal is burnt in presence of oxygen, its weight is increased by 25%. the equivalent weight of the metal will be?
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Equivalent weight of O2-(oxide) ion is : Molar mass of oxygen/charge on oxygen
= 16 g mol-1 /2 mol eq-1
= 8 g eq-1
One equivalent of the metal reacts with one equivalent of oxygen to form metal oxide.
Let M be the equivalent weight of the metal.
Therefore M grams of the metal will react with 8g of oxygen. The corresponding metal oxide will have mass 8 gram more than mass of metal M. This 8 gram is 25% of M.
Or we can say that M x 25/100 = 8 gram
So, M = 100 x 8/25 = 32g
= 16 g mol-1 /2 mol eq-1
= 8 g eq-1
One equivalent of the metal reacts with one equivalent of oxygen to form metal oxide.
Let M be the equivalent weight of the metal.
Therefore M grams of the metal will react with 8g of oxygen. The corresponding metal oxide will have mass 8 gram more than mass of metal M. This 8 gram is 25% of M.
Or we can say that M x 25/100 = 8 gram
So, M = 100 x 8/25 = 32g
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