. When a metallic ball bearing is placed inside a cylindrical container of radius 2 cm, the height of the water inside the container increases by 0.6 cm. The radius to the nearest tenth of a centimeter of the ball bearing is
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When a metallic ball is placed inside a cylinder with a portion of it filled with water , it displaces volume of water equivalent to the volume of the ball and there by rising the height of the water in the cylinder.
volume of a cylinder = 2 * pi * r * h
r= radius of the cylinder
h = height of the cyinder
pi = 3.14
SO , volume of water displaced = 2* pi * 2 * 0.6
let radius of ball be R cms
Then , its volume = 4 * pi * R^3
Equating both of them ,
2 * pi * 2 * 0.6 = 4 * pi * R^3
we get, R = 0.5646216173 cms
volume of a cylinder = 2 * pi * r * h
r= radius of the cylinder
h = height of the cyinder
pi = 3.14
SO , volume of water displaced = 2* pi * 2 * 0.6
let radius of ball be R cms
Then , its volume = 4 * pi * R^3
Equating both of them ,
2 * pi * 2 * 0.6 = 4 * pi * R^3
we get, R = 0.5646216173 cms
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