Question

When a metallic surface is illuminated by light of wavelength 2lamda?

Answer 1

 

1 Answer

Answer :  4λ4λ

Explanation :

Einstein's photoelectric equation :

hcλ=e(3V0)+W−−−−(1)hcλ=e(3V0)+W−−−−(1)

Here W=work function ; and hcλ=e(V0)+W−−−−(2)hcλ=e(V0)+W−−−−(2)

Solving equations

(1)-(2)

hcλ=3hc2λ−W−3Whcλ=3hc2λ−W−3W

2W=hc2λ2W=hc2λ

hcλ0=hc4πhcλ0=hc4π

λ0=4λwhenλ0=λ0=4λwhenλ0= threshold wavelength