when a mixture of 10 moles of SO2 and 16 moles of O2 WERE PASSED OVER A CATALYST ,8 MOLES OF SO3 WERE FORMED AT EQUILIBRIUM .THE NO. OF MOLES OF OF SO2 AND O2 REMAINING ARE
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SO2 moles remained 2
and 12 moles of O2 remained
and 12 moles of O2 remained
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2SO2(g)+O2(g)--------->2SO3(g)
t=0 10 16 0
teq.(10-2x) (16-x) 2x
2x=8,ie.,x=4
RemainingSO2=10-8=2mol
RemainingO2=16-4=12mol
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