Question

When a mixture of iron and steam was allowed to come to equilibrium at 900C,
it was found that the equilibrium pressure of hydrogen and steam were 0.00950
atm and 0.00650 atm respectively. Calculate the equilibrium constant for the
reaction and the percentage of steam that is reduced, if steam at 1.00 atm is
admitted into an iron vessel and allowed to come to equilibrium.
3Fe(s) + 4H2O(g) Fe3O4(s) + 4H2(g)

Answer 1

Answer:

3Fe(s) + 4H2O(g) Fe3O4(s) + 4H2(g)

Explanation:

00C,

it was found that the equilibrium pressure of hydrogen and steam were 0.00950

atm and 0.0065

Answer 2

Answer ☝️.

3Fe(s) + 4H2O(g) Fe3O4(s) + 4H2(g)