Question

When a monochromatic yellow coloured light beam is incident on a given

photosensitive surface, photoelectrons are not ejected, while the same surface

gives photoelectrons when exposed to green coloured monochromatic beam.

What will happen if the surface is exposed to: (i) red coloured,

monochromatic beam of light? Justify your answer.​

Answer 1

Answer:

No photoelectrons are emitted.

Explanation:

Yellow has greater frequency than green.

Yellow didn't made it eject electrons while green did.

This tells us that wavelength and frequency is the barrier for differentiation b/w the two.

So red has greater wavelength and less frequency which made it not eject any electrons while greater frequency and less wavelength of green made it eject electrons.

Thank you.

Answer 2

There will be no photo-electronic emission when the red colour is incident on the given surface.

Explanation:

When a photosensitive surface is energized using the yellow monochromatic light then there is no emission of photo-electrons.

But when the same surface is exposed to the monochromatic green light then we observe the photoelectronic emission, this indicates that the energy imparted to the surface by the yellow light was less than the threshold energy required for the photo-emission.

As we know that the energy of photons is given as:

$E=h.\nu$

where:

h = Planck's constant

$\nu=$ frequency of the monochromatic source

Now as we move form the violet colour towards the red colour in the visible spectrum the frequency of the light decreases hence the energy of the photons decreases.

So, there will be no photo-electronic emission when the red colour is incident on the given surface.

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TOPIC: work function

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