When a natural number ‘a’ is divided by another natural number ‘b’, if the quotient is ‘t’ and remainder is ‘r’ then ‘a’ can be uniquely expressed as a = tb + r where 0 LaTeX: \le≤r LaTeX: <<b , a > b. Let a = 666………6 consisting of 666 sixes. Then....
For b = 50, the value of r is_____
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Answer: r=1 by calculating
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