Question

When a number is added to two-thirds of itself, the result is 55. Find the number.​

Answer 1

Answer:

Hi ,

Let the number = x

Two thirds of the number = 2x/3

According to the problem given,

x + 2x/3 = 55

( 3x + 2x ) /3 = 55

5x / 3 = 55

x = ( 55 × 3 ) / 5

x = 11 × 3

x = 33

Therefore ,

Required number = x = 33

I hope this helps you.

:)

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Let the number be x.

First part of the problem: a no. Added to the 2/3rd of its own.

x + (2/3)x

Second part: is equal to 55

x + (2/3)x = 55

=> (5/3)x=55

=> x= (55*3)/5

=>x=11*3

=> x=33

Hence,the original number is 33.

Rechecking through answer.

If 33 is the original number, Lets check if 22 is its 2/3rd.

33*(2/3)=>11*2=>22

Hence proved.

hope it helps uh...