when a number is divided by 9 the remainder is 7 . if twice the number is divided by 9 then remainder is ?
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let x is the number when divided by 9 , remainder is 7
so , x = 9y + 7
now twice of its is , 2x
x + x = 9y + 7 + 9y + 7
twice of a number = 9 × 2y + 14
but , 14 = 9 × 1 + 5
so ,
twice of a number = 9 × 2y + 9 × 1 + 5
twice of a number = 9 × (2y+1) + 5
so remainder is 5
so , x = 9y + 7
now twice of its is , 2x
x + x = 9y + 7 + 9y + 7
twice of a number = 9 × 2y + 14
but , 14 = 9 × 1 + 5
so ,
twice of a number = 9 × 2y + 9 × 1 + 5
twice of a number = 9 × (2y+1) + 5
so remainder is 5
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