When a number is subtracted from its square, the result is 42. Find the number.
Answers
Answered by
2
Answer:
You are wording it wrong. The way you have it worded you end up with imaginary numbers.
You are wording it wrong. The way you have it worded you end up with imaginary numbers.When a number is subtracted from its square the result is 42 !
You are wording it wrong. The way you have it worded you end up with imaginary numbers.When a number is subtracted from its square the result is 42 !x^2-x=42
You are wording it wrong. The way you have it worded you end up with imaginary numbers.When a number is subtracted from its square the result is 42 !x^2-x=42x^2-x-42=0
You are wording it wrong. The way you have it worded you end up with imaginary numbers.When a number is subtracted from its square the result is 42 !x^2-x=42x^2-x-42=0(x-7)(x+6)=0
You are wording it wrong. The way you have it worded you end up with imaginary numbers.When a number is subtracted from its square the result is 42 !x^2-x=42x^2-x-42=0(x-7)(x+6)=0x-7=0
You are wording it wrong. The way you have it worded you end up with imaginary numbers.When a number is subtracted from its square the result is 42 !x^2-x=42x^2-x-42=0(x-7)(x+6)=0x-7=0x=7
You are wording it wrong. The way you have it worded you end up with imaginary numbers.When a number is subtracted from its square the result is 42 !x^2-x=42x^2-x-42=0(x-7)(x+6)=0x-7=0x=77^2-7=49-7=42
You are wording it wrong. The way you have it worded you end up with imaginary numbers.When a number is subtracted from its square the result is 42 !x^2-x=42x^2-x-42=0(x-7)(x+6)=0x-7=0x=77^2-7=49-7=42x+6=0
You are wording it wrong. The way you have it worded you end up with imaginary numbers.When a number is subtracted from its square the result is 42 !x^2-x=42x^2-x-42=0(x-7)(x+6)=0x-7=0x=77^2-7=49-7=42x+6=0x=-6
You are wording it wrong. The way you have it worded you end up with imaginary numbers.When a number is subtracted from its square the result is 42 !x^2-x=42x^2-x-42=0(x-7)(x+6)=0x-7=0x=77^2-7=49-7=42x+6=0x=-6(-6)^2-(-6)=36-(-6)=36+6=42
You are wording it wrong. The way you have it worded you end up with imaginary numbers.When a number is subtracted from its square the result is 42 !x^2-x=42x^2-x-42=0(x-7)(x+6)=0x-7=0x=77^2-7=49-7=42x+6=0x=-6(-6)^2-(-6)=36-(-6)=36+6=427 and -6 are the numbers
Answered by
2
Answer:
There are two numbers which satisfy the criteria
x
=
6
,
x
=
−
7
Explanation:
Let the number be
=
x
, this number is added to its square
x
2
x
+
x
2
=
42
Now, we solve the equation in order to find
x
x
2
+
x
−
42
=
0
We first factorise the expression.
We can Split the Middle Term of this expression to factorise it.
x
2
+
x
−
42
=
x
2
+
7
x
−
6
x
−
42
=
x
(
x
+
7
)
−
6
(
x
+
7
)
=
(
x
−
6
)
(
x
+
7
)
Equating the factors to zero we get two values for
x
x
=
6
,
x
=
−
7
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