Question

when a number N is divided by a proper divisor D then it leaves a remainder of 14 and if the thrice of that number that is 3N is divided by the same divisor D, the reminder comes out to be 8. Again if the 4 times the same number that is 4N is divided by D the remainder will be ? 1. 35 2. 22 3. 5 4. can't be determine

Answer 1

Step-by-step explanation:

use the formula

dividend = (divisor * quotient) + remainder

you have given that

dividend = N, 3N, 4N

divisor = D

remainder = 14, 8, ?

put these values in equation and form three different equation and try to eliminate N, D and quotient.

you will get your ans.

Answer 2

Answer:

Step-by-step explanation:

When N is divided by D the remainder is 14. When 3*N is divided by D the remainder should be 3*14 = 42. However, we get 8 as the remainder. Therefore, the divisor should be 42–8 = 34.

Let us check our answer. Suppose the number is 34+14 = 48.

When 48 is divided by 34, we get 14 as the remainder. When 144 is divided by 34 we get 8 as the remainder. When 4*48 = 192 is divided by 34 we get 22 as the remainder.

We have one more option. The divisor can also be 17. In that case, the number is 31.

When 31 is divided by 17 the remainder is 14. When 93 is divided by 17 we get 8 as the remainder. When 4*31 = 124 is divided by 17 we get 5 as the remainder.

Hence, the remainder could be either 5 or 22.

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