Question

When a object is move towards a concave mirror with speed 'a' m/s. Then what is the speed of image when the object is at a distance 'x' m. from the mirror? (given that 'f' is the focal length of the mirror.)​

Answer 1

Answer:

Adding (1) and (3),

(x + y)(a + b) = (a + b)/(a - b)

x + y = 1/(a - b)

x = [1/(a - b)] - y ----- (4)

From (4) and (1),

ax + by = 1

[a/(a - b)] - ay + by = 1

y(b - a) = 1 - [a/(a - b)]

y(b - a) = -b/(a - b)

y = b/[(b - a)^2] = [b/(a - b)^2] ----- (5)

From (5) and (4),

x = [1/(a - b)] - y

x = [1/(a - b)] - [b/(a - b)^2]

x = [1/(a - b)] - [b/(a - b)^2]

x = (a - 2b)/(a - b)^2Explanation:

Answer 2

Answer:

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