Math, asked by tejaskalpande, 5 months ago

When a owner sells his house for Rs. 26400, he loses 20%. At what price should he have sold the house in
order to get profit of 12%?​

Answers

Answered by tamannasharma31
12

Answer:

ANSWER

Selling Price of each house =Rs.246400

Gain =12% on one house

Loss =12% on other house

CP of the house with gain =SP−Profit=246400−

100

12

×CP

CP of the house with gain =

112

246400×100

=220000

CP of the house with loss =SP+Loss=246400+

100

12

×CP

CP of the house with loss =

88

246400×100

=280000

Total CP =220000+280000=Rs.500000

Total SP =2×246400=492800

Thus, loss=CP−SP=500000−492800=Rs.7200

Answered by DevendraLal
2

If we consider we have 100 means 100% percent value of number 100

We decrease 20 % means 100-20=80

So apply the unitary method

80 = 26400 means 26400/80=330

So one unit value is 330

Then we have to calculate the 12% profit on the actual value of the house.

Then

Increasing the 12% on a hundred means 112

So,

Multiply one unit value into 112

Means

112*330 =36960

In order to receive the profit one should sell the property for more than its cost and he is selling for 12% profit and the selling cost is 36,960.

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