Question

When a particle carrying a charge of 0.000001 coulombs is brought from infinity ta a point P, 0.002 joules work is done. What is the potential at point P​

Answer 1

Given:

A particle carrying a charge of 0.000001 C = $10^{-6}$C.

It is brought from infinity to point P.

Work done = 2 x $10^{-3}$ J.

To Find:

The potential at point P​.

Solution:

Given a charge q is moved from point A to point B.

Then the electric potential difference between the points are given by,

• Va - Vb = -W/q ,
• Where W is the work done  for moving it.

Potential at infinity is taken to be zero.

• V∞ - Vp  = - W/q
• -Vp = -W/q
• Vp = W/q
• Vp = 2 x $10^{-3}$ / $10^{-6}$ = 2 x 10 ³ J/C

The  potential at point P is  2 x 10 ³ J/C.