Question

when a particle carrying a charge of 0.000001 coulombs is brought from infinity to a point P 0.02 joules of work is done what is the potential at point P ​

Answer 1

Answer:

w=q(∆v)

Explanation:

we know that the potential at infinity is zero

so,w=q(v`-v).

let v`be the potential at P and v be the potential at infinity

w=0.000001(v`-0)

0.02=0.000001(v)

v=20000 volts