Question

When a particle carrying a charge of 10 x 10-6 coulombs is brought from infinity to a point P. 2 x 10-3 Joules of work is done. What is the potential at the point P?​

Answer 1

Electric potential at a point is defined as the amount of work done per unit positive charge in bringing that unit positive charge from infinity to that point.

Electric potential at the point P = $\frac{2 \times {10}^{ - 3} }{10 \times {10}^{ - 6} } volt \\ = \frac{10^{ - 3} }{5 \times {10}^{ - 6} } \: volt \\ = \frac{ {10}^{ - 3 + 6} }{5} volt \:$

$= \frac{ {10}^{3} }{5} volt \\ = \frac{1000}{5} volt \\ = 200 \: volt$