When a particle executes simple harmonic motion, its kinetic energy varies periodically with a period of 2 s. The time period of simple harmonic motion is
plz give me right ans.
no spamiing plz
Answers
Answered by
0
Explanation:
Let displacement of particle of mass m, x=Asinωt
ω=angular frequency of oscillation
frequency, f=
2π
ω
velocity v=
dt
dx
=ωAcosωt
So, K.E=
2
1
=mv
2
=
2
1
mω
2
A
2
cos
2
ωt
=
4
1
mω
2
A
2
(1+cos(2ωt))
Now for kinetic energy the cosine part determine frequency which is
f
′
.
2π
2ω
.
π
ω
−2ω
⇒f
′
.2f
Answered by
0
Answer:
Mark as Brainlinet answer
Attachments:
Similar questions