Chemistry, asked by nagmanisha, 3 months ago

When a particle executes simple harmonic motion, its kinetic energy varies periodically with a period of 2 s. The time period of simple harmonic motion is


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Answers

Answered by orio2914
0

Explanation:

Let displacement of particle of mass m, x=Asinωt

ω=angular frequency of oscillation

frequency, f=

ω

velocity v=

dt

dx

=ωAcosωt

So, K.E=

2

1

=mv

2

=

2

1

2

A

2

cos

2

ωt

=

4

1

2

A

2

(1+cos(2ωt))

Now for kinetic energy the cosine part determine frequency which is

f

.

.

π

ω

−2ω

⇒f

.2f

Answered by sinhaniveditasinha
0

Answer:

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