Question

When a particle is projected at some angles to the horizontal,it has a range R and time of flight t1. If the same particle is projected with same speed at some other angle to have the same range its time of flight is t2, then,
1. t1 + t2 = 2R/g
2. t1 - t2 = R/g
3. t1t2 = 2R/g
4. t1t2 = R/g

Answer 1

The range for both the projectile is R.
The time for the first projectile is t1 and for the second projectile is t2.
Let,and angle of projection are theta and (90°- theta) for the projectiles respectively..
Therefore option 3 is correct...

Answer 2

3rd option is correct