Question

When a particle is thrown vertically upwards then its velocity such that it covers same distance in 5th and 6th second will be?

Answer 1

Answer:

answered below

Explanation:

distance S(t) = ut - gt²/2 = ut - 5t² , g = 10

distance covered in5th second =  S(5) - S(4) = u - 45 = d1

distance covered in 6th second = S(6) - S(5) = u - 55 = d2

but d1 ≠ d2

they will not be the same whatever the velocity may be ....