Physics, asked by physco13, 9 hours ago

When a particle moves in a horizontal circle with angular velocity w,, the centripetal force is F. When it moves in the same circle with angular velocity w2, the centripetal force is 2F. What is the value of w2/w1?​

Answers

Answered by MoonBlaze
2

Answer:

Given equations is

x+2y=8,5x+10y=c

The equations a

1

x+b

1

y=c

1

and a

2

x+b

2

y=c

2

will have uique solutions if

a

2

a

1

=

b

2

b

1

=

c

2

c

1

but from equations,

a

2

a

1

=

5

1

,

b

2

b

1

=

10

2

,

c

2

c

1

=

c

8

a

2

a

1

=

b

2

b

1

The given equations does not have unique solution, so the given statement is false, The correct answer is 0

Answered by Yuhanji
1

Answer:

The centripetal force is equal to

In our article on centripetal acceleration, we learned that any object traveling along a circular path of radius r with velocity v experiences an acceleration directed toward the center of its path, a = v 2 r a = \frac{v^2}{r} a=rv2a, equals, start fraction, v, squared, divided by, r, end fraction.

Explanation:

hope this helps :)

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