Question

When a particle of charge 10 c is brought from infinity to a point p , 2.0 j of work is done by the external forces. what is the potential at p?

Answer 1

Charge Q = 10 x 10-6 C
Work done W = 2 x 10-3 J
Potential at P = V = W/Q = 2 x 10-3 J/(10 x 10-6 C)
= 2 x 102 V = 200 V.

Answer 2

Answer:

given,

q= 10 millicoulomb

or q= 10 x 10^-6 coulomb

w= 2.0 mJ

or w= 2 x 10^-3 joules

potential at point P = v= w/q

= 2 x 10^-3/ 10 x 10^6

= 2 x 10^2 v

therefore, potential at point P = 200v