Question

When a particle of charge 10 uC is brought from infinity to point in the electric field, 10mj work is done by the external force. What is the potential at that point?

Answer 1

Hii friend,

The formula is,

Work done= potential ×charge

potential =work done/charge

potential= 10×10-³/10 ×10^-6

potential (V)=10³V (or)1000V.

Hope this helps you a little!!!

Answer 2

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Potential difference = 1000V

$\red{\mid{\underline{\overline{\textbf{explanation}}}\mid}}$

Work is said to be done when a force is applied on a body and the body undergoes displacement.

In field of electricity work is the ratio of potential difference to the total charge. It is represented by the equation :

$\bigstar \: \orange{\mid{\underline{\overline{\textbf{w = v÷q}}}\mid}}$

In this equation :

• w = work done
• v = potential difference
• q = total charge

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In this question we have been given that 10Megajoule of work is done in moving a charge of 10Uc , potential difference in this case is not known, we have to calculate it.

In this question :

Work done = 10Mj = 10^ -3J

Total charge = 10Uc

Potential difference = v = ?

Now, after inputting the known values in the equation we get :-

$\mapsto \: v = \frac{10 \times {10}^{ - 3} }{10 \times {10}^{ - 6} }$

$\mapsto \: v = 1000volt$

Therefore potential difference of system is 1000V.

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BY SCIVIBHANSHU

THANK YOU

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