Question

When a person leaves his home for sightseeing by his car, the meter reads 12352km.when he returns home after two hours the reading is12416km.(a) what is the average speed of the car during this period?(b) what is the average Velocity?

Answer 1

$\huge\textbf{Solution}$
$<b><i>$

Initial reading of the meter= 12352 km

Final reading of the meter= 12416 km

Distance Covered= (12416 km-12342 km)

= 64 km

The average speed of the car during this period is

= Total distance travelled/ Total time Taken

$= \frac{62}{2}km /hr$

= 32 km/hr

$average \: velocity = \frac{displacement}{time}$

Displacement is  shortest distance between final and initial position.

So ,Displacement will be Zero because initial and final position is same

ஃThe average velocity is zero

Thanks

Have a colossal day ahead

Be Brainly

Answer 2

Holla ^_^


☸ Required Answer is ⬇⬇ ⬇⬇ ⬇



⭕ Total Distance = 12416-12352 = 64 km
Total Time = 2 hrs
Displacement = 0


A.T.Q

a). Average Speed = Total distance/Total time

= 64/2 => 32km/h


b). Average Velocity = Displacement/time
=0/2 => 0



=> Average Speed = 42km/h
=> Average Velocity = 0


Vielen Dank ♥