when a piece of wood is is submerged in water it floats with 1/4 part outside and when the same solid is sub merged in any another liquid then it floats with 1/3 part outside then calculate the density of the wood and the liquid no place for spammers spammer will be reported
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The answer for your question is 1.5m/3
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Archimedes principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged is equal to the weight of the fluid that the body displaces and acts in the upward direction at the centre of mass of the displaced fluid. So, for an object to float Weight of object (Buoyant force) density of an object volume of object density of liquid Volume of disp. liquid Volume above the liquid density of water A/Q cube in water From Cube in liquid From From As So,
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