Question

When a polynomial 2x2+3x2+ax+b is divided by x-2 leaves remainder 2,and X+2 leaves remainder-2. Find a and b

Answer 1

Answer:

Step-by-step explanation:

Here ,

2x^3 +3x^2 +ax+b -2 = 0, as by dividing this equation by x-2 it leaves remainder 2 so i subtract 2 from it.

Now, by putting x= 2

2a+b = -26

Again doing the same process ,

2x^3 +3x^2 +ax+b +2= 0,

By putting x= -2

-2a+b= 2

By solving both the equations

a= -7

b= -12

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