Question

when a polynomial 2x³+3x²+ax+bid divided by (x-2)leaves a remainder 2,and (x+2)leaves. aremainder -2. Find a and b...........
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Answer 1

Answer:

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Step-by-step explanation:

a(x) ^3 +4(x)^2+3x‑4 Now x=3 , put the value of x which is 3 f(3) = a(3) ^3 +4(3) ^2+3(3) ‑4... (i) 27a+36+9‑4 27a+41=0....(ii) (x) ^3‑4(x)+a 3^3‑4(3) +a 27‑12+a 15+a=0....(iii) As the remainder is same , we equate the eqs(ii) &(iii) 27a+41=15+a 26a=‑26 a=‑1 ‑1 is the answer... If iam not worng... Hope the answer help you...

Answer 2

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