When a polynomial f(x) is divided by (x-1) then the remainder is 5 and when it is divided by (x-2) then the remainder is 7. Find the remainder when it is divided by (x-1)(x-2).
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Answer:
two equations remainder r(x) =2x+3
Step-by-step explanation:
Let us assume the polynomial to be f(x) .
When f(x) is divided by (x−1) , we get the remainder as 5 .
Therefore, f(1)=5
When f(x) is divided by (x−2) , we get the remainder as 7 .
Therefore, f(2)=7
Now, when same polynomial f(x)
is divided by (x−1)(x−2) , the remainder is given by:
f(x)=q(x).(x−1)(x−2)+r(x)
When, x=1
⇒f(1)=0.(x−2)q(1)+r(1)=5
When, x=2
⇒f(2)=0.(x−1)q(2)+r(2)=7
Solving above two equations, we get remainder r(x)=2x+3
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