When a polynomial f(x) is divided by x-3 and x+6 , the respective remainders are 7 and 22. What is the remainder when f(x) is divided by (x-3)(x+6)
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Let the remainder be represented by Ax + B
If f(x) is divided by x-3, remainder is 7
=> 3A + B = 7
If f(x) is divided by x-(-6), remainder is 22
=> -6A + B = 22
Solving the two equations, we get A = -15/9 & B = 12
So final remainder is -15x/9 + 12
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