When a polynomial f(x) is divided by x-3 and x+6 , the respective remainders are 7 and 22. What is the remainder when f(x) is divided by (x-3)(x+6)
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When polynomial f(x) = x^2 + 4/3 x - 6 is divided by x-3 and x+6 the remainders are 7 and 22.
When f(x) = x^2 + 4/3 x - 6 is divided by (x-3)(x+6) the remainder is -5/3 x +12
I let one solution be f(x) = x^2 + bx + c and solved for b and c by dividing by (x-3) and (x+6) and by equating remainders to 7 and 22 solved for b and c.
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