When a polynomial p(x) is divided by (x - 1), the remainder is 3. When p(x) is divided by (x - 3), the
remainder is 5. If r(x) is the remainder when p(x) is divided by (x - 1) (X - 3), then the value of r(-2) is :
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Answer:
r(2)=0
Step-by-step explanation:
When p(x) is divided by (x - 1), the remainder is 3.
so p(1)=3
and When p(x) is divided by (x - 3), the remainder is 5.
so p(3)=5
Let r(x)= ax+b
So p(x) =(x-1)(x-3)k + r(x)
p(x) =(x-1)(x-3)k + ax +b
So on putting x=1
P(1)=a+b=3----------------------(1)
and p(3)=3a+b=5------------(2)
on subtracting (1) from(2)we get
2a=2,a=1
And from(1)
1+b=3,b=2
THus r(x)=ax+b=x+2
And r(-2)=-2+2=0
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