Question

when a powder was treated with dilute HCl a gas was produced and when a lighted matchstick is shown to it, the flame was put off and gas did not start burning.
(a) name the Powder
(b) give reason for the observation shown

Answer 1

HELLO FRIEND HERE IS YOUR ANSWER,,,,,,,,,

Given substance or powder when it's treated with dilute Hydrochloric Acid. When a gas was produced by that reaction, a burning or lighted matchstick was shown towards the gas which basically puts off the Flame completely and gas production in it stops too.

This query can be explained by a carbonate which is generally attached to the element of Sodium. That is, when The compound or the powder of sodium carbonate or $\bf{Na_2CO_3}$ when brought to a lighted matchstick it releases Carbon Dioxide gas as a waste product when they're thoroughly having a reaction with dilute acids. In this case the dilute acid is Hydrochloric acid.

The formation of Carbon dioxide gas or $\bf{CO_2}$ doesn't support the property which is in particular needed called as $\bf{Combustion}$ because of which the flames go off from the matchstick.

HOPE THIS HELPS YOU AND CLEARS THE DOUBTS FOR SUPPORTABLE COMPLETE COMBUSTION!!!!!!

Answer 2

Answer:

The powder is Calcium Carbonate . Calcium carbonate reacts with acidic solutions to produce carbon dioxide gas. It is this reaction that is responsible for limestone fizzing when dilute hydrochloric acid is placed on its surface.

The equation is :CaCO3(s) + 2HCl(aq) →CO2 (g) +H2O(l) + CaCl2 (aq)

hope this helps you....

Mark as brainliest