When a pressure measuring device is immeresed in a liquid, a restoring force of 2 N is exerted by the spring. If the area of cross-section of the piston is 10 cm square, what pressure does the fluid exert on the piston
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The pressure experienced in both cases would be same. So, as
P = F/A
F1/A1 = F2/A2
or the force on the second piston will be
F2 = (F1/A1).A2
by substituting appropriate values we get
F2 = (F1/A1).A2
F2 = (2 / 10x10-4). 100 x 10-4
F2 = 2 x 10 ^3
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