When a proton is released from rest in a room, it starts with
an initial acceleration a₀ towards west. When it is projected
towards north with a speed v₀ it moves with an initial
acceleration 3a₀ towards west. The electric and magnetic
fields in the room are respectively [2013]
(a) ma₀/e west, 2ma₀/ev₀ down
(b)ma₀/e east, 3ma₀/ev₀ up
(c) ma₀/e east, 3ma₀/ev₀ down
(d) ma₀/e west, 2ma₀/ev₀ up
Answers
Answered by
1
Answer:
F
1
= electric force acting on the proton in west direction
q= charge on proton
E= electric field in the region in west direction
m= mass of proton
electric force on the proton can be given on F
1
=qE
Using Newton's second law
F
1
=ma
0
hence,
ma
0
=qE
E=ma
0
/q Along west
Case -2
V
0
= initial velocity of the particle
F
2
= magnetic force acting on the proton in west direction electric force on proton =3ma
0
F
1
+F
2
=3ma
0
ma
0
+F
2
=3ma
0
maximum magnetic force is given by
F
2
=qV
0
B
So, qV
0
B=2ma
0
B=2ma
0
/qV
0
(down).
Option C
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