Question

when a radiation is incident on a metal emitter the maximum velocity of ejected electron are found to be 2×10^6 calculate the stopping potential maximum kinetic energy of photo electron given charge to mass ratio e/m=1.8×10^11c/kg​

Answer 1

Explanation:

If e//m for the electrons is 1.8 xx 10^(11) C kg^(-1) the maximum velocity of the ejected electrons is. =√2×1.8×1011×9=1.8×106m/s