Physics, asked by RESHSHAIK, 4 months ago

When a resistance of 60,000 ohm is connected in
series with a voltmeter, the combination now can
measure five times more voltage than the original
voltmeter. The initial internal resistance of the
voltmeter is​

Answers

Answered by sk515162662
0

Explanation:

240,000

i hope this is useful for you

Answered by priyanjali1312373
1

Answer: Let us consider resistance=G

V1/V2 = R1/R2

1/5 = G/ G+60000

G+60000 = 5G

4G = 60000

G = 15000ohm

Explanation:

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