When a resistor is placed across 230 v supply the dc current is 12a what is the value of resistance that must b connected in parallel to increase the load current to 16 a?
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V =i*R
Where v is the potential difference across the resistance, I current passing through the resistance and R resistance of the resistor
Now given condition
220 =R1* i
R1 =220/12
220/R2 =16
R2= 220/16
1/R2=1/R1+1/r
16/220=12/220+1/r
1/r =4/220
r =220/4=55
So the connected resistance r =55 ohm in parallel to the resistor.
Where v is the potential difference across the resistance, I current passing through the resistance and R resistance of the resistor
Now given condition
220 =R1* i
R1 =220/12
220/R2 =16
R2= 220/16
1/R2=1/R1+1/r
16/220=12/220+1/r
1/r =4/220
r =220/4=55
So the connected resistance r =55 ohm in parallel to the resistor.
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