when a rod is heated from 25 degree Celsius to 75 degree celsius it expands by 1 mm rod of same material but with 4 times the length is heated from 25 degree Celsius to 50 degree Celsius increase in length is
Answers
Answer:
From the first case we can find the coefficient of volume expansion be using the formulae of change in length/ original length*temperature difference.
Which we will get the Υ which we take as the coefficient of volume expansion
will be 1/L*25.
In the second case the temperature difference is the same but the original length is four times than the previous. So, if we take the change in length as x then equation will be x/4L25 = 1/L*25 which on solving we will get the increase in length or x to be 4mm.
Answer:
Explanation:
From the first case we can find the coefficient of volume expansion be using the formulae of change in length/ original length*temperature difference.
Which we will get the Υ which we take as the coefficient of volume expansion
will be 1/L*25.
In the second case the temperature difference is the same but the original length is four times than the previous. So, if we take the change in length as x then equation will be x/4L25 = 1/L*25 which on solving we will get the increase in length or x to be 4mm.