When a rubber-band is stretched by a distance x, it exerts a restoring force of magnitude F = ax + bx2 where a and b are constants. The work done in stretching the unstretched rubber band by L is
A) aL2/2 + bL3/3
B) (aL2 + bL3)/3
C) aL2 + bL3
D) (aL2/2 + bL3/3)/2
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Answered by
2
Answer: option A
Explanation: check the attached photo
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Answered by
1
Answer:
A
Explanation:
Restoring force : F = ax+bx²
we know that work done = ∫F.dx
here w = ∫(0 to L) (ax+bx²).dx
= [ax²/2+bx³/3] 0 to L (∵by integration)
∴ w = aL²/2+bL³/3
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