Question

When a rubber band is stretched by a distance x, it exerts a restoring force of magnitude F = ax+bx² , where a and b are constant . the work done in stretching the unstratched rubber band by L is ? ​

Answer 1

Explanation:

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Answer 2

Explanation:- As ,we know that change in potential energy of a shystem corresponding to a conservative internal force as

• Uf - Uᵢ = -W = - ᵢ∫ᵗ F dr

Given :- F = ax+ bx²

• According to work energy theorem , we know that work done in stretching the rubber band by t is
• |dw| = Fdx
• |W| = ₀∫ᴸ (ax+bx²) dx
• ⟹ [ax²/2]₀ᴸ+ [bx²/3]₀ᴸ
• ⟹[aL²/2-a×(0)/2]² + [bL³/3-b×(0)³/3]
• ⟹|W|= aL²/2 + bL³/3 Answer

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