when a salesman walks at 4km/h to reach the bus stop he misses his bus by 10 min if he walk at 5 km/h. he reches the bus stop 5 min before the bus arrive how far is house from the bus?
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Answer:
5km
Step-by-step explanation:
let the distance between the house and the bus be = x.
so time taken in first case to reach the bus = x/4.
time taken in second case to reach the bus = x/5.
the salesman reaches the bus 10 min after its departure and 5 min before its departure in the second case. So the difference is 15 min or 15/60 hr.
so... T1 - T2 = 15/60.
x/4 -x/5 =15/60.
x=5km
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