Math, asked by jitenderkmr924, 9 months ago

when a salesman walks at 4km/h to reach the bus stop he misses his bus by 10 min if he walk at 5 km/h. he reches the bus stop 5 min before the bus arrive how far is house from the bus?​

Answers

Answered by futurekingx
0

Answer:

5km

Step-by-step explanation:

let the distance between the house and the bus be = x.

so time taken in first case to reach the bus = x/4.

time taken in second case to reach the bus = x/5.

the salesman reaches the bus 10 min after its departure and 5 min before its departure in the second case. So the difference is 15 min or 15/60 hr.

so... T1 - T2 = 15/60.

x/4 -x/5 =15/60.

x=5km

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