Question

When a screw gauge of least count 0.01 mm is used to measure the diameter of a wire, the reading on the sleeve is found to be 1 mm and the reading on the thimble is found to be 27 divisions. (i) What is the diameter of the wire in cm ? (ii) If the zero error is + 0.005 cm, what is the correct diameter ?​

Answer 1

Answer:

0.122 cm is your answer

Answer:

diameter of the wire = 0.127 cm

correct diameter = 0.122 cm

Explanation:

given, L.C. = 0.01mm

n = 27

M.S.R = 1 mm

Diameter of the wire = M.S.R + C.S.R

1 + n × L.C

1 + 27 × 0.001

1 × 0.27 = 1.27 mm

0.127 cm

correct diameter = observed diameter - zero error

0.127 - (+0.005)

0.122 cm