Physics, asked by rrudransh366, 2 months ago

When a screw gauge of the least count 0.01 mm is used to measure the diameter of the wire, the linear scale reading is 2 mm and 28th division of circular line coincides with the reference line. What is the diameter of the wire? If the screw gauge has a zero error of -0.04 mm, calculate the corrected diameter of the wire.​

Answers

Answered by rcbaplawatuncle
1

Answer:

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Answered by Sagar9040
1

Least count =

Diameter = M. S. +( No. of division coinciding with main scale × Least count.)

= 1 mm + 47 × 0.01 mm

= 1.47 mm = 0.147 cm.

Curved surface area = πdL =

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