Question

When a shaft is subjected to a bending moment M and a twisting moment T, then the equivalent twisting moments is equal to

Answer 1

Answer:

The correct Answer is

✓(M²+T²)

Answer 2

Answer:

√(M² + T²)

Explanation:

• When a shaft experiences pure bending, normal stress arises.
• When a shaft experiences a pure twisting moment, shear stress emerges.
• When the shaft is subjected to pure twisting, shear stress is created (torsion). At the shaft's axis, the shear stress resulting from the twisting moment is zero.
• Torsional stiffness is the result of shear modulus (C) and polar moment of inertia (J).
• Principal stress is created when bending and torsion work together.
• The greatest shear stress produced by torsion alone is equivalent to the maximum shear stress produced by bending and torsion combined (Equivalent Bending TM).
• Equivalent Bending BM: This BM is the one that, when used alone, generates a maximum normal stress that is equal to the maximum normal stress generated by bending and torsion combined.

$T_{eq}=\sqrt{M^2+T^2}\\ M_{eq}=1/2 (M+\sqrt{M^2+T^2} )$

#SPJ2