Question

When a shot-putter exerts a net fore of 140 N on a shot, the shot has an
acceleration of 19 m/s2. What is the mass of the shot?​

Answer 1

$\Large\underline{\underline{\red{\sf \purple{\maltese}\:\: Given :- }}}$

$\sf \implies The \ shot \ putter \ exerts \ a force \ of \ 140 N . \\\sf \implies The \ shot \ has\ an \ accl^n \ of \ 19m/s^2.$

$\Large\underline{\underline{\red{\sf \purple{\maltese}\:\: To \ Find :- }}}$

$\sf\implies The \ mass \ of \ the \ shot.$

$\Large\underline{\underline{\red{\sf \purple{\maltese}\:\: Let :- }}}$

$\sf\implies Mass \ of \ the \ shot \ = \ m_{shot}$

$\Large\underline{\underline{\red{\sf \purple{\maltese}\:\: Answer :- }}}$

Given that a shot putter exerts a force of 140 N on the shot. The shot has an acceleration of 19m/s². And we need to find the mass of the shot . We know that Force is the product of mass and acceleration . So ,

$\sf :\implies \green{ Force = mass \times accl^{n} }\\\\\sf:\implies 140 N = m_{shot} \times 19m/s^2 \\\\\sf:\implies m_{shot} = \dfrac{140N}{19m/s^2} \\\\\boxed{\purple{\sf \implies Mass_{shot} = 7.36 kg }}$

Hence the mass of the shot is 7.36 kg .