Question

when a single dice is thrown, there are six possible outcomes, 1, 2, 3, 4, 6.The probablity of anyone of them is______​

Answer 1

Answer:-

No of favourable outcomes, n(e) = 1

Total No of possible of outcomes, n(s) = 6

p(e) = n(e) / n(s)

p(e) = 1/6

Answer 2

AnswEr:

probability of getting any one of them is $\bold{\dfrac{1}{6}}$.

ExplanaTion:

When a single dice is thrown :

Possible outcomes = 1, 2, 3, 4, 5, 6

So, Total Outcomes = 6

Now, for getting any one of them,

Favourable Outcomes = 1

We know that,

$\large{\boxed{\rm{Probability_{(e)}\:=\:\dfrac{Favourable\:Outcomes}{Total\:Outcomes}}}}$

: $\implies$ Probability of getting anyone of them = $\dfrac{1}{6}$

Hence, probability of getting any one of them is $\bold{\dfrac{1}{6}}$.