When a single-lens camera is focused at distant object, the lens-to film distance is found to be 40.0 mm. To focus on an object 0.54 mm in front of lens, the film-to-lens distance must be
Answers
Explanation:
Focal length, f=6cm
u=1.5m=150cm
v=?
f
1
=
v
1
−
u
1
6
1
=
v
1
+
150
1
v
1
=
6
1
−
150
1
=
150
25−1
v=
24
150
=
12
75
=
4
25
=6.25
change in distance =6.25−6=0.25cm
=0.25cm=2.5mmdecreased
~kuku
The film-to-lens distance must be 40.56 mm to focus on an object 0.54 mm in front of the lens.
To find,
The film-to-lens distance
Given,
Distance is found to be 40.0 mm.
An object 0.54 mm in front of the lens.
Solution,
The lens equation is given by:
1/f = 1/di + 1/do
where f is the focal length of the lens, di is the image distance, and do is the object distance.
When a single-lens camera is focused on a distant object, the lens-to-film distance is equal to the image distance, di = 40.0 mm. Let's assume the focal length of the lens is f.
1/f = 1/di + 1/do
1/f = 1/40.0 mm + 1/infinity
1/f = 1/40.0 mm
f = 40.0 mm
So the focal length of the lens is 40.0 mm.
To focus on an object 0.54 mm in front of the lens, we can use the lens equation again, this time with the object distance, do = -0.54 mm (since the object is in front of the lens):
1/f = 1/di + 1/do
1/40.0 mm = 1/di + 1/(-0.54 mm)
Solving for di, we get:
di = -0.56 mm
The negative sign indicates that the image is formed on the same side of the lens as the object, which is expected for a single-lens camera.
Since the image distance is negative, we can find the film-to-lens distance by taking the absolute value of the image distance and adding it to the lens-to-film distance:
df = |di| + di = |-0.56 mm| + 40.0 mm = 40.56 mm
Therefore, the film-to-lens distance must be 40.56 mm to focus on an object 0.54 mm in front of the lens.
For further reference about the film-to-lens,
https://brainly.in/question/18247233?referrer=searchResults
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