Question

When a single resistor is connected to a battery, a total power P is dissipated in the circuit. How much total
power is dissipated in a circuit if n identical resistors are connected in series using the same battery? Assume
the internal resistance of the battery is zero.
(A) n
2P (B) nP (C) P (D) P/n

Answer 1

Answer:

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Answer 2

The total power dissipated in a circuit if 'n' identical resistors are connected in series using the same battery is :

(D) P/n

This can be calculated in the following ways:

• Power can be represented as (P) = P = ε²/R

• As per the question, there are n resistors.

• Thus the total resistance is = nR

• Therefore, P' = ε²/nR

                              = P/n